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In fig. 6.2 bac 90° and ad  bc. then

WebOct 19, 2024 · In ∠BAC = 90° and AD ⊥ BC. A Then (а) BD.CD = BC² (б) AB.AC = BC² (c) BD.CD = AD² (d) AB.AC = AD² Answer 11. D and E are respectively the points on the sides AB and AC of a triangle ABC such that AD = 2 cm, BD = 3 cm, BC = 7.5 cm and DE BC. Then, length of DE (in cm) is (a) 2.5 (b) 3 (c) 5 (d) 6 Answer 12. WebMar 29, 2024 · Example 10 In figure, ∠ ACB = 90° and CD ⊥ AB. Prove that BC2/AC2=BD/AD Given:- ΔCAB, ∠ ACB = 90° And CD ⊥ AB To Prove :- BC2/AC2=BD/AD Proof : From theorem 6.7, If a perpendicular is drawn from the vertex of the right angle to the hypotenuse then triangles on both sides of the Perpendicular are similar to the whole triangle and to ...

In Fig., ∠BAC = 90° and AD ⊥ BC. The number of right triangles in …

WebAug 5, 2024 · In the given figure, ∠A = 90°, AD ⊥ BC. If BD = 2 cm and CD = 8 cm, find AD. (2012; 2024D) Solution: ∆ADB ~ ∆CDA … [If a perpendicular is drawn from the vertex of the right angle of a rt. ∆ to the hypotenuse then As on both sides of the ⊥ are similar to the whole D and to each other ∴ … [∵ Sides are proportional AD 2 = BD , DC WebIn Fig. 6.2, ∠BAC = 90° and AD BC. Then, a. BD . CD = BC 2 b. AB . AC = BC 2 c. BD . CD = AD 2 d. AB . AC = AD 2. Solution: Given, ∠BAC = 90° Also, AD BC. We know that a … north carolina boat shows https://productivefutures.org

In fig 6.2 angle BAC =90° and AD perpendicular to BC - Brainly

WebApr 11, 2024 · In the given figure, if ∠BAC = 90° and AD⏊BC. Then, (A) BD.CD = AD2 (B) AB.AC = AD2 (C) BD.CD = AD2 (D) AB.AC = AD2 Ans: The correct option is (C): BD·CD = AD2 In ΔADB and ΔADC, It is given that ∠BDA = ∠ADC = 90° ∠B = ∠DAC = (90°- C) Now, by AA similarity criterion $\triangle \mathrm {ADB} \sim \triangle \mathrm {CDA}$ WebMar 16, 2024 · Given: ABC is a triangle where ABC < 90 and AD BC To Prove: AC2 = AB2 + BC2 2BC.BD Proof: In right APB By Pythagoras Theorem, AB2 = AD2 + BD2 In right ADC By Pythagoras Theorem, AC2 = AD2 + CD2 From (2) AC2 = AD2 + CD2 AC2 = AD2 + (BC BD)2 AC2 = AD2 + BD2 + BC2 2BC.BD Putting AD2 + BD2 = AB2 from equation (1) AC2 = AB2 + … WebMar 22, 2024 · Transcript. Show More north carolina boat insurance

In Fig. 6.2, ∠BAC = 90° and AD ⊥ BC. Then - [MCQ

Category:MCQ Questions for Class 10 Maths Triangles with Answers

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In fig. 6.2 bac 90° and ad  bc. then

Example 10 - ACB = 90 and CD perpendicular AB. Prove BC2/AC2

WebSolution In ΔADE and ΔABC, ∠A= ∠A (Common angle) ∠ADE= ∠B (Given) So by AA similarity, triangles are similar. So, by CPCT, AD AB= DE BC 3.8 3.6+2.1 = DE 4.2 DE = 3.8×4.2 5.7 = 2.8 Suggest Corrections 15 Similar questions Q. In the given figure, if ∠ADE = ∠B, AD = 3.8 cm, AE = 3.6 cm, BE = 2.1 cm and BC = 4.2 cm, find DE. Q. WebGiven, ABC is an equilateral triangle with AD as altitude. We have to find the value of 4AD². We know that in an equilateral triangle all the sides are of equal length. Let AB = BC = AC = x units ----- (1) Let AD = h units ----- (2) In an equilateral triangle, the altitude AD bisects BC. So, BD = CD = BC/2 = x/2

In fig. 6.2 bac 90° and ad  bc. then

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WebMar 7, 2024 · In the given figure, angle BAC = 90° and AD perpendicular BC. Then, A)BC.CD = BC² B)AB.AC =BC² C) BD.CD = AD² D)AB.AC = AD² Answer: Option C) BD.CD = AD² … WebJun 28, 2024 · In a quadrilateral ABCD, ∠A + ∠D = 90°. Prove that AC 2 + BD 2 = AD 2 + BC 2 [Hint: Produce AB and DC to meet at E] Solution: Given : Quadrilateral ABCD, in which ∠A + …

Webiii In Fig. 6.2,∠BAC=90∘and AD⊥. BC. Then, 4 Fig. 6.. Answer Answered By toppr How satisfied are you with the answer? This will help us to improve better answr Get Instant Solutions, 24x7 No Signup required download app More Questions by difficulty EASYMEDIUMHARD Prev QuestionNext Question Related Questions to study

WebExample 5: In Fig. 6.3, PS is the bisector of ∠P and PQ = PR. Then ∆PRS and ∆PQS are congruent by the criterion (a) AAA (b) SAS (c) ASA (d) both (b) and (c) Fig. 6.3 Solution : … WebIn an equilateral triangle ABC (Fig. 6.2), AD is an altitude. Then 4AD² is equal to a. 2BD² b. BC² c. 3AB² d. 2DC². Solution: Given, ABC is an equilateral triangle with AD as altitude. We …

Web1. In figure, if ∠BAC =90° and AD⊥BC. Then, (a) BD.CD = BZC² (b) AB.AC = BC² (c) BD.CD=AD² (d) AB.AC =AD². Solution: c) BD.CD=AD². Explanation: From ∆ADB and ∆ADC, …

WebMar 29, 2024 · Transcript. Ex 6.2, 4 In figure, DE AC and DF AE. Prove that, prove that 𝐵𝐹/𝐹𝐸 = 𝐵𝐸/𝐸𝐶 Given: DE II AC and DF II AE To prove: 𝐵𝐹/𝐹𝐸=𝐵𝐸/𝐸𝐶 Proof: From (1) and (2) 𝐵𝐹/𝐹𝐸=𝐵𝐸/𝐸𝐶 Hence proved. Next: Ex 6.2, 5 Important → Ask a doubt. Chapter 6 Class 10 Triangles. north carolina bona fide discount pointsWebEngineering Civil Engineering Curved panel BC in Fig. P2.96 is a 60° arc, perpend lar to the bottom at C. If the panel is 4 m wide into paper, estimate the resultant hydrostatic force of … north carolina board of veterinary medicineWebIn figure, if ∠BAC =90° and AD⊥BC. Then, (a) BD.CD = BZC² (b) AB.AC = BC² (c) BD.CD=AD² (d) AB.AC =AD² Solution: c) BD.CD=AD² Explanation: From ∆ADB and ∆ADC, According to the question, we have, ∠D = ∠D = 90° (∵ AD ⊥ BC) ∠DBA = ∠DAC [each angle = 90°- ∠C] Using AAA similarity criteria, ∆ADB ∼ ∆ADC BD/AD = AD/CD BD.CD = AD 2 2. north carolina board optometryWebMar 29, 2024 · Question 3 In Fig. 6.2, ∠BAC = 90° and AD ⊥ BC. Then, BD . CD = BC2 (B) AB . AC = BC2 (C) BD . CD = AD2 (D) AB . AC = AD2 From Theorem 6.7, If a perpendicular is … Transcript. Question 4 The lengths of the diagonals of a rhombus are 16 cm and … north carolina boat titlingWebQuestion In fig if ∠ADE=∠ABC ,then show that ADE∼ ABCand AD=6.8 cm, AE =8.6 cm, BE=2.4 cm and BC = 5.5 cm Find DE A 5.4 cm B 4.6 cm C 3.4 cm D None of these Medium Solution Verified by Toppr Correct option is C) Consider the diagram given in the question. ∠A is common in both the triangles, ADE and ABC. Also, ∠ADE=∠B how to request days off in outlookWeb>> In figure, BAC = 90^o and AD BC . Then Question In figure, ∠BAC=90 o and AD⊥BC. Then A BD.CD=BC 2 B AB.AC=BC 2 C BD.CD=AD 2 D AB.AC=AD 2 Easy Solution Verified by … north carolina body style codesWebAug 1, 2024 · Solution: The figure is attached below In Triangle ABC, angle BAC = 90 degree and AD is perpendicular to BC Given in the question a perpendicular is drawn AD on BC from angle BAC which is 90 degree So, these two triangles ABD and CAD are similar By Corresponding part of Similar Triangles (CPST), how to request dbs certificate